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JAMB UTME - Physics - 1988

Question 1 Report

When white light is dispersed by a spectrometer, the component having the shortest wavelength is

orange

green

violet

red

View Answer

Question 6 Report

A particle starts from rest and moves with a constant acceleration of 0.5ms-2. The distance covered by the particle in 10s is

2.5m

5.0m

25.0m

50.0m

Answer Details

X = ut +

\frac{1}{2}

at

= (0 x 10) + ( $\frac{1}{2}$ x 0.05 x 10 x 10)

= 25m

Read lesson note on Motion (JAMB)

View Answer

Question 9 Report

A body whose mass is 2kg and has a volume of 500cm just floats when completely immersed in a liquid. Calculate the density of the liquid

4.0 x 102kgm-3

4.0 x 103kgm-3

1.0 x 103kgm-3

1.0 x 106kgm-3

Answer Details

since the object floats, density of liquid = density of object

D = $\frac{m}{v}$

= $\frac{2}{500 \times 10}$

= 4.0 x 103kgm-3

Read lesson note on Pressure (JAMB)

View Answer

Question 13 Report

A tap supplies water at 25oC while another supplies water at 75oC. If a man wishes to bathe with water at 40oC, the ratio of the mass of cold water to the mass of hot water required is

1 : 3

15 : 8

7 : 3

3 : 1

Answer Details

Heat lost = heat gained

mh x c x (75 - 40) = mc x c x (40 - 25)

$\frac{m_{h}}{m_{c}}$ = $\frac{35}{15}$

= $\frac{7}{3}$

Read lesson note on Heat Energy (WAEC)

Heat Energy

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Question 18 Report

How long will it take a 60kg man to climb a height of 22m if he expended energy at a rate of 0.25kW. [g = ms-2]

5.3s

34.5s

41.6s

52.8s

Answer Details

power = mgh

0.25 x 103 = $\frac{60 \times 10 \times 22}{t}$

t = 52.8 sec

Read lesson note on Work, Energy And Power (WAEC)

Work, Energy And Power

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Question 19 Report

An object is placed 10cm in front of a concave mirror of focal length 15cm. What is the position and nature of the image formed?

30cm and virtual

6cm and real

6cm and virtual

30cm and real

Answer Details

F =

\frac{u v}{u + v}

15 = $\frac{10 \times v}{10 + v}$

v = -30cm

Read lesson note on Electrostatics (JAMB)

Electrostatics

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Question 24 Report

In a certain fusion reaction, a deuteron (\({}^{2}_{1}\mathrm{H}\)) interacts with a triton (\({}^{3}_{1}\mathrm{He}\)) and produces an a-particle (\({}^{4}_{2}\mathrm{He}\)) and a second product. The second product is

a proton

an electron

a neutron

a gamma ray

Answer Details

_{1}^{2} H

+

_{1}^{3} H

\to

_{2}^{4} H e

+

_{0}^{1} H e

Read lesson note on Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

View Answer

Question 25 Report

When taking a penalty kick, a footballer applies a force of 30.0N for a period of 0.05s. if the mass of the ball is 0.075kg, calculate the speed with which the ball moves off.

4.50ms-1

11.25ms-1

20.00ms-1

45.00ms-1

Answer Details

F =

\frac{m (v - u)}{T}

30 = $\frac{0.75 (v - 0)}{0.05}$

v = 20ms-1

Read lesson note on Equilibrium Of Forces (WAEC)

Equilibrium Of Forces

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Question 26 Report

A piano wire 0.5m long has a total mass of 0.01kg and is stretched with a tension of 800N. Calculate the frequency of the wire when it sounds its fundamental note

200Hz

100Hz

4Hz

2Hz

Answer Details

F =

\frac{1}{2 L}

\sqrt{\frac{T}{m}}

N:B m is mass per length

= $\frac{0.01}{0.5}$

= 0.02kgm-1

F = $\frac{1}{2 \times 0.5}$ $\sqrt{\frac{800}{0.02}}$

= 200Hz

Read lesson note on Work, Energy & Power (JAMB)

Read lesson note on Elasticity (JAMB)

Work, Energy & Power

View Answer

Question 27 Report

Which of the following symbolic representations is correct for an atom X with 22 electrons and 43 neutrons?

43	X
22

22	X
43

_{43}^{65} X

_{22}^{65} X

Structure Of The Atom (Nigeria Only)

View Answer

Question 28 Report

A cell of internal resistance 2 ohms supplies current to a 6 ohms resistor. The efficiency of the cell is

12.0%

25.0%

33.3%

75.0%

Answer Details

Efficiency =

\frac{I R}{I (R + r)}

x 100

= $\frac{6}{I (2 + 6)}$ x 100

= 75%

Read lesson note on Current Electricity (JAMB)

Current Electricity

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Question 30 Report

Two forces whose resultant is 100N, are at right angle to each other. If one of them makes an angle 30o with the resultant, determine its magnitude.

8.66N

50.0N

57.7N

86.6N

Answer Details

COS 30o =

\frac{F_{1}}{100}

F1 = 86.6N

Read lesson note on Scalars And Vectors (WAEC)

Scalars And Vectors

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Question 31 Report

A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s-1, the angular speed of the larger wheel is

3 rev s-1

40 rev s-1

360 rev s-1

2400 rev s-1

Answer Details

\frac{speed of driver}{speeder driven}

=

\frac{no. of teeth of driver}{no. of teeth of driven}

$\frac{120}{V}$ = $\frac{20}{60}$

v = 360 rev s-1

Read lesson note on Motion (JAMB)

Read lesson note on Mass And Weight (WAEC)

Mass And Weight

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Question 33 Report

The product PV where P is pressure and V is volume has the same unit as

force

power

energy

accelaration

Answer Details

PV =

\frac{N}{m^{2}}

x

\frac{m^{2}}{1}

= Nm

Read lesson note on Measurements And Units (JAMB)

Measurements And Units

View Answer

Question 36 Report

Two strings of the same length and under the same tension gives notes of frequencies in the ratio 4 : 1. The masses of the strings are in the corresponding

2 : 1

1 : 2

1 : 4

1 : 16

Answer Details

F =

\frac{1}{2 L}

\sqrt{\frac{T}{m}}

$\frac{F_{1}}{F_{2}}$ = $\sqrt{\frac{m_{2}}{m_{1}}}$

$\frac{1}{4}$ = $\sqrt{\frac{m_{2}}{m_{1}}}$

$\sqrt{\frac{m_{2}}{m_{1}}}$ = $\frac{1}{2}$

Read lesson note on Motion (JAMB)

View Answer

Question 42 Report

To obtain a magnification of 2.5, how far should an object be placed from the pole of a thin converging lens of focal length 10.20m?

0.13m

0.25m

0.28m

0.50m

Answer Details

v = 2.5u

F = $\frac{u v}{u + v}$

0.2 = $\frac{u \times 2.5 u}{u + 2.5 u}$

u = 0.28m

Read lesson note on Reflection Of Light At Plane And Curved Surfaces (JAMB)

Read lesson note on Simple A.C Circuits (JAMB)

Read lesson note on Electrostatics (JAMB)

Reflection Of Light At Plane And Curved Surfaces

Simple A.C Circuits

Electrostatics

View Answer

Question 43 Report

A force, 10N, drags a mass 10kg on a horizontal table with an acceleration of 0.2ms. If the acceleration due to gravity is 10ms-1, the coefficient of friction between the moving mass and the table is

0.02

0.08

0.20

0.80

Answer Details

μ

mg = ma

$μ$ x 10 x 10 = 10 x 0.2

$μ$ = 0.02

Read lesson note on Newton’s Laws Of Motion (WAEC)

Read lesson note on Measurements And Units (JAMB)

Newton’s Laws Of Motion

Measurements And Units

View Answer

Question 44 Report

When a resistance R is across a cell, the voltage across the terminals of the cell is reduced to two-third of its normal value. The internal resistance of the cell is

\frac{2}{1}

R

\frac{1}{2}

R

\frac{3}{2}

R

5R

Answer Details

IR =

\frac{2}{3}

I(R + r)

r = $\frac{1}{2}$ R

Read lesson note on Current Electricity (JAMB)

Read lesson note on Scalars And Vectors (JAMB)

Current Electricity

Scalars And Vectors

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