JAMB UTME - Physics - 1998 | Green Bridge CBT

Question 1 Report

The atmospheric pressure due to water is 1.3 x 106Nm-2. What is the total pressure at the bottom of an ocean 10m deep? [Density of water = 1000kgm-3, g = 10ms-2]

1.3 x 107Nm-2

1.4 x 106Nm-2

1.4 x 105Nm-2

1.0 x 10 5Nm-2

Answer Details

Pressure = heg = 1000 x 10 x 10 = 105Nm-2

Total pressure = (1.3 x 106) + (1 x 105)

= 1.4 x 106Nm-2

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Question 2 Report

In photoelectric effect, electrons will leave the metal surface when illuminated by light of appropriate frequency if the photon energy is

greater than the work function

less than the work function

equal to the work function

equal to the maximium kinetic energy of the electron

Answer Details

In the photoelectric effect, when light shines on a metal surface, electrons can be emitted from the surface of the metal. The energy of the photons in the light is transferred to the electrons, which can overcome the binding energy of the metal and escape from its surface. The minimum amount of energy required to remove an electron from the metal surface is called the work function. If the energy of the photons is less than the work function, the electrons cannot overcome the binding energy and will not be emitted from the surface. On the other hand, if the energy of the photons is greater than or equal to the work function, the electrons can be emitted. Therefore, to answer the question, if the photon energy is greater than the work function, the electrons will leave the metal surface when illuminated by light of appropriate frequency in the photoelectric effect. Answer "greater than the work function," is the correct answer.

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Read lesson note on Structure Of The Atom (Nigeria Only) (WAEC)

Wave-particle Paradox

Structure Of The Atom (Nigeria Only)

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Question 3 Report

A vapour is said to be saturated when

more molecules return to the liquid than the amount that left it

a dynamic equilibrium exists between the molecules of the liquid and the vapour molecules at a given temperature

the vapour pressure is equal to the atmospheric pressure

all molecules are moving with the same speed in all directions at a given temperature

Answer Details

A vapour is said to be saturated when a dynamic equilibrium exists between the molecules of the liquid and the vapour molecules at a given temperature. This means that the rate of evaporation of the liquid is equal to the rate of condensation of the vapour, resulting in a constant amount of vapour in the air. At this point, the vapour has reached its maximum capacity to hold water molecules, and any additional water molecules added to the system will result in condensation.

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Vapours

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Question 4 Report

One valid assumption of the kinetic theory of gasses is the

the molecules of a gas are constantly in a state of motion and the number of collision remains constant

the number of molecule of gas increases with increasing pressure

as the temperature increases, the number of collision made by the gas molecule remains constant

the molecules of gas are all identical and are very small in size

Thermal Expansion

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Question 5 Report

An object is placed in front of two plane mirrors inclined at an angle of $0^\circ$. If the total number of images formed is 7, Find the value of $\theta$

30o

45o

51o

90o

Answer Details

Number of image =

\frac{360}{θ}

-1

7 = $\frac{360}{θ}$ -1

thus, $θ$ = 45o

Read lesson note on Electrostatics (JAMB)

Electrostatics

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Question 6 Report

In a nuclear fusion experiment, the loss of mass amounts to 1.0 x 10-6kg. The amount of energy obtained from the fusion is

3.0 x 10-4J

3.0 x 10-1J

9.0 x 104J

9.0 x 1010J

Answer Details

Energy = mc2

= 1 x (3 x 108)2 x 106

= 9 x 1010J

Read lesson note on Magnetic Field (Part 2) (WAEC)

Magnetic Field (Part 2)

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Question 7 Report

Which of these statements are correct for the pressures in liquids? i. pressure in a liquid at a point acts equally in all directions. ii. pressure increases with depth. iii. pressure at a depth depends on the shape of the container. iv. pressure at the same depth in different liquids are proportional to the density at different liquids.

i, ii, iii only

i, ii, iv only

i, iii, iv only

ii, iii, iv only

Temperature And Its Measurement

Pressure

Liquids At Rest

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Question 8 Report

In a wheel and axle mechanism the diameters of the wheel and axle are 40cm and 8cm respectively. Given that the machine is 80% efficient, what effort is required to lift a load of 100N?

20N

25N

50N

80N

Answer Details

The wheel and axle mechanism is a simple machine used for lifting heavy loads. The mechanical advantage of a wheel and axle mechanism is given by the ratio of the radius of the wheel to the radius of the axle. In this case, the diameters of the wheel and axle are given, and so we need to calculate their radii. The radius of the wheel, r_w, is half the diameter of the wheel, so r_w = 20 cm. Similarly, the radius of the axle, r_a, is half the diameter of the axle, so r_a = 4 cm. The mechanical advantage of the wheel and axle mechanism is given by: MA = r_w / r_a Substituting the values we get: MA = 20 cm / 4 cm = 5 The efficiency of the machine is given as 80%, which means that 80% of the work put into the machine is used to lift the load. The remaining 20% is lost due to friction and other factors. Efficiency = (Output work / Input work) x 100% Since the output work is equal to the weight lifted (100 N) times the distance moved by the load, and the input work is equal to the effort required to lift the load times the distance moved by the effort, we can write: Efficiency = (100 N x d) / (E x d) x 100% where d is the distance moved by both the load and the effort. Simplifying this expression gives: Efficiency = 100 / MA Substituting the value of MA gives: 80% = 100 / 5 So, the effort required to lift a load of 100N is: E = (100 N x d) / (Output work) E = (100 N x d) / (Efficiency x Input work) Substituting the values of efficiency, output work and input work, we get: E = (100 N x d) / (0.8 x E x 5 x d) Simplifying this expression, we get: E = 25 N Therefore, the effort required to lift a load of 100N is 25N. Hence, the correct option is 25N.

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Read lesson note on Simple Machines (JAMB)

Pressure

Simple Machines

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Question 9 Report

A platinum resistance thermometer records $3.0\,\Omega$ at $0^\circ\mathrm{C}$ and $8.0\,\Omega$ at $100^\circ\mathrm{C}$. If it records $6.0\,\Omega$ in a certain environment, The temperature of the medium is

80oC

60oC

50oC

30oC

Answer Details

8

Ω

.....100oC

6 $Ω$ ..... $θ$ oC

3 $Ω$ .....0oC

$\frac{6 - 3}{8 - 3}$ = $\frac{θ - 0}{100 - 0}$

therefore, $θ$ = 60oC

Read lesson note on Temperature And Its Measurement (JAMB)

Temperature And Its Measurement

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Question 10 Report

A gas has a volume of 100cm3 at 27oC. If it is heated to temperature T until a final volume of 120cm3 is attained, calculate T

33oC

60oC

87oC

114oC

Answer Details

This question can be solved using the gas laws, specifically Charles's law which states that at constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature. We are given that the initial volume of the gas is 100 cm^3 at a temperature of 27 degrees Celsius. We need to find the temperature T at which the final volume of 120 cm^3 is attained. Since the pressure is constant, we can use Charles's law to solve for T. First, we need to convert the initial temperature of 27 degrees Celsius to its absolute temperature (in kelvin). We do this by adding 273 to 27 to get 300K. Next, we use the formula for Charles's law: V1/T1 = V2/T2 where V1 is the initial volume (100 cm^3), T1 is the initial temperature in kelvin (300K), V2 is the final volume (120 cm^3), and T2 is the final temperature in kelvin (which we are solving for). Substituting the values, we get: 100/300 = 120/T2 Cross-multiplying and simplifying, we get: T2 = 120 x 300 / 100 = 360K Finally, we need to convert the temperature in kelvin back to degrees Celsius by subtracting 273. So the final answer is: T2 = 360 - 273 = 87°C Therefore, the answer is 87°C.

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Gas Laws

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Question 11 Report

The physical properties of sound waves can best be described by

reflection and diffraction

polarization and reflection

polarization and diffraction

polarization and refraction

Reflection Of Light At Plane And Curved Surfaces

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Question 12 Report

A body on the ground is acted on by a force of 10N at a point P as shown in the fig above. What force is needed to stop the body from moving eastwards

5N in the direction of east

5N in the diretion of west

5V3N in the direction of west

10N in the southwest direction

Scalars And Vectors

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Question 13 Report

The iron core of an induction coil is made from bundles of wire so as to

minimize eddy-currents

generate eddy-current

prevent sparking at the contact breaker

get the greatest posible secondary voltage

Answer Details

An induction coil is a device that converts low voltage into high voltage, and it does this by inducing an electric current in a coil of wire. The iron core of an induction coil is made from bundles of wire so as to minimize eddy-currents. Eddy currents are small, swirling currents of electricity that can be generated in the core of the coil when an alternating current is passed through it. These eddy currents can cause heating, energy loss, and interfere with the operation of the coil. By making the core from bundles of wire, the eddy currents are minimized, and the induction coil operates more efficiently. Therefore, the correct option is "minimize eddy-currents."

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Read lesson note on Position, Distance And Displacement (WAEC)

Electromagnetic Field (Part 2)

Position, Distance And Displacement

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Question 14 Report

The force of attraction between two point masses is 10-4N when the distance between them is 0.18m. If the distance is reduced to 0.06m, calculate the force.

1.1 x 10-5N

3.3 x 10-5N

3.0 x 10-4N

9.0 x 10-4N

Answer Details

The force of attraction between two point masses is given by the equation: F = G * (m1 * m2) / r^2 where F is the force of attraction, G is the gravitational constant, m1 and m2 are the masses of the two point masses, and r is the distance between them. In this case, we know that the force of attraction between the two point masses is 10^-4 N when the distance between them is 0.18m. We can use this information to find the value of G * (m1 * m2): G * (m1 * m2) = F * r^2 G * (m1 * m2) = (10^-4 N) * (0.18 m)^2 G * (m1 * m2) = 3.24 x 10^-6 N m^2 Now, if the distance between the two point masses is reduced to 0.06m, we can use the same equation to find the new force of attraction: F = G * (m1 * m2) / r^2 F = (G * (m1 * m2) / (0.06 m)^2 F = (3.24 x 10^-6 N m^2) / (0.06 m)^2 F = 9 x 10^-4 N Therefore, the force of attraction between the two point masses is 9 x 10^-4 N when the distance between them is reduced to 0.06m. So the correct option is: 9.0 x 10^-4 N

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Gravitational Field

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Question 15 Report

Which of the following can be used to reduce local action in a Laclanche cell?

A carbon rod as the positive pole

Pure zinc as the negative pole

Potassium permanganate solution in contact with the positive pole

common salt solution

Electric Cells

Conduction Of Electricity Through

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Question 16 Report

Electricity is supplied to a school along a cable of total resistance $0.5\,\Omega$ with the maximum current drawn from the mains as $100\text{ A}$. The maximum energy dissipated as heat for $1\text{ hr}$ is

3.6 x 103J

5.0 x 103J

3.0 x 105J

1.8 x 107J

Answer Details

Electricity supplied to a school through a cable has a certain resistance. This means that as current flows through the cable, some of the electrical energy is lost as heat due to the resistance of the cable. The amount of energy lost as heat is given by the formula: Energy = Current^2 x Resistance x Time In this question, we are given the resistance of the cable and the maximum current drawn from the mains, which is 100A. We are also told that we need to calculate the maximum energy dissipated as heat for 1 hour (which is 60 minutes). Using the formula above, we can calculate the maximum energy dissipated as heat as follows: Energy = Current^2 x Resistance x Time Energy = 100^2 x 0.5 x 3600 (since 1 hour = 3600 seconds) Energy = 18,000,000 J Energy = 1.8 x 10^7 J Therefore, the maximum energy dissipated as heat for 1 hour is 1.8 x 10^7 J. The correct option is: - 1.8 x 107J

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Question 17 Report

A parallel plate capacitor has a common plate area of $5 \times 10^{-8}\,\mathrm{m}^2$ and plate separation of $2 \times 10^3\,\mathrm{m}$, Assuming free space, What is the capacitance? [$\epsilon_o = 9.0 \times 10^{-12}\,\mathrm{C}^2\mathrm{N}^{-1}\mathrm{m}^{-2}$]

2.25 x 10-17F

4.50 x 10-17F

2.25 x 10-16F

4.50 x 10-16F

Answer Details

C =

\frac{ε_{o} A}{d}

= $\frac{5 \times 10^{- 8} \times 10^{- 12} \times 9}{2 \times 10^{- 3}}$

= 22.5 x 10-17F

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Capacitors

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Question 18 Report

A man wears convex lens glasses of focal length 40cm in order to correct his eye defect. instead of the optimum 25cm, his least distance of distinct vision is

14cm

28cm

75cm

150cm

Answer Details

A person with an eye defect has difficulty seeing objects clearly, especially those that are close to them. The defect may be due to the shape of the eye, which prevents light from being focused correctly on the retina. A convex lens can be used to correct this defect by converging the light before it enters the eye, thus allowing the eye to focus the image correctly. The focal length of a lens is a measure of its ability to converge light. A lens with a shorter focal length is more powerful and can converge light more strongly than a lens with a longer focal length. For a person with an eye defect, the focal length of the lens must be chosen to compensate for the defect and provide the correct amount of convergence. In this question, the man wears convex lens glasses with a focal length of 40cm to correct his eye defect. However, his least distance of distinct vision is not the optimum distance of 25cm. The least distance of distinct vision is the minimum distance at which an object can be seen clearly. To find the least distance of distinct vision for this man, we can use the lens equation: 1/f = 1/di + 1/do Where f is the focal length of the lens, di is the distance of the image from the lens, and do is the distance of the object from the lens. For the man to see an object at his least distance of distinct vision, the image formed by the lens must be at infinity (di = infinity). Plugging these values into the lens equation and solving for do gives: 1/40 = 1/infinity + 1/do 1/do = 1/40 do = 40cm Therefore, the man's least distance of distinct vision is 40cm. The correct answer to the question is "150cm," which is not among the answer options provided.

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Electric Field

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Question 19 Report

A solid of weight 0.600N is totally immersed in oil and water respectively. If the upthrust of oil is 0.210N and the relative density of oil is 0.875. Find the upthrust in water.

0.600N

0.360N

0.240N

0.180N

Answer Details

Rd =

\frac{upthrust in oil}{upthrust in H_{2} O}

thus; 0.875 = $\frac{0.21}{upthrust in H_{2} O}$

upthrust in H2O = 0.24N

Read lesson note on Gravitational Field (JAMB)

Gravitational Field

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Question 20 Report

An ebonite rod rubbed with fur attracts a glass rod rubbed with silk because

ebonite has a negative charge while glass has a positive charge

ebonite has a positive charge while glass has a negative charge

both have negative charges

both have positive charges

Answer Details

When two objects are rubbed against each other, they can become electrically charged. This happens because the rubbing causes electrons to transfer from one object to the other. One object loses electrons and becomes positively charged, while the other gains electrons and becomes negatively charged. In this case, when the ebonite rod is rubbed with fur, it gains electrons and becomes negatively charged. When the glass rod is rubbed with silk, it loses electrons and becomes positively charged. Opposite charges attract each other, so the negatively charged ebonite rod and positively charged glass rod will be attracted to each other. Therefore, the correct answer is that the ebonite rod has a negative charge while the glass rod has a positive charge.

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Electrostatics

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Question 21 Report

The force of repulsion between two point positive charges $5\,\mu\text{C}$ and $8\,\mu\text{C}$ separated at a distance of $0.02$ map art is. $\left[\dfrac{1}{4\pi\varepsilon_o}=9 \times 10^9\text{ Nm}^2\text{C}^{-2}\right]$

1.8 x 10-10N

9.0 x 10-8N

9.0 x 102N

4.5 x 103N

Answer Details

F =

\frac{1}{4 π ε_{o}}

x

\frac{q_{1} q_{2}}{r^{2}}

F = $\frac{5 \times 10 \times 8 \times 10}{0.002 \times 0.002}$ x 9 x 10

F = 900N

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Properties Of Waves: Reflection, Refraction, Diffraction

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Question 22 Report

A man whose mass is 80kg climbs a staircase in 20s and expends power of 120W. Find the height of the staircase.[g = 10ms-2]

1.8m

2.0m

2.5m

3.0m

Answer Details

To solve this problem, we need to use the formula for power: Power = work done / time taken We also need to use the formula for work done: Work done = force x distance The force here is the weight of the man, which is given by: Force = mass x gravity where g is the acceleration due to gravity. We can rearrange the formula for work done to get the distance: Distance = work done / force Combining these formulas, we get: Power = force x distance / time taken We can rearrange this to get: Distance = Power x time taken / force Substituting the given values: Distance = 120 x 20 / (80 x 10^-2) = 300m Therefore, the height of the staircase is 300m. However, this answer seems unreasonable because it is very high. We need to check if we made an error. We can use another formula to check: Distance = 1/2 x acceleration x time taken^2 where acceleration = gravity. Substituting the values: Distance = 1/2 x 10 x 20^2 = 2000m This is an even higher value, which confirms that we made an error. On closer inspection, we can see that we forgot to convert the mass to weight. Weight = mass x gravity = 80 x 10 = 800N Using this value, we can recalculate the distance: Distance = Power x time taken / force = 120 x 20 / 800 = 3m Therefore, the height of the staircase is 3m. Hence, the correct option is: 3.0m.

Read lesson note on Work, Energy And Power (WAEC)

Work, Energy And Power

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Question 23 Report

The total resistance measured at PQ in the diagram above is

18.0Ω

11.0Ω

4.0Ω

2.0Ω

Current Electricity

Measurements And Units

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Question 24 Report

Find the work done in moving a 2 C charge between two points X and Y in an electric field if the potential difference is 100 volts

50J

100J

200J

400J

Answer Details

The work done in moving a charge in an electric field is given by the formula: W = qΔV Where W is the work done, q is the charge, and ΔV is the potential difference between the two points. In this problem, the charge is 2 C and the potential difference between the two points X and Y is 100 volts. Therefore, using the formula above, we get: W = 2 C x 100 V = 200 J Therefore, the work done in moving a 2 C charge between two points X and Y in an electric field with a potential difference of 100 volts is 200 J. Answer 200J, is the correct answer.

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Electric Field

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Question 25 Report

In a closed organ pipe producing a musical note, an antinode will always be produced at

the closed end

the open end

the middle

all the parts of the pipe

Answer Details

In a closed organ pipe, the air column is closed at one end, and open at the other. When a sound wave is produced, it travels down the length of the pipe and is reflected at the closed end. This reflection causes a standing wave pattern to form within the pipe, with points of maximum vibration called antinodes and points of no vibration called nodes. Since the air column at the closed end is prevented from moving, it creates a node at that point. Therefore, the antinode will always be produced at the open end of a closed organ pipe producing a musical note. This is where the air column is free to vibrate, resulting in maximum displacement and maximum amplitude of the sound wave. So, the correct answer is: "the open end."

Read lesson note on Temperature And Its Measurement (JAMB)

Read lesson note on Propagation Of Sound Waves (JAMB)

Temperature And Its Measurement

Propagation Of Sound Waves

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Question 26 Report

The velocity of a sound wave at 27oC is 360ms-1. Its velocity at 127oC is

120√3 ms-1

240 ms-1

240√3 ms-1

720√3 ms-1

Answer Details

Velocity

α \sqrt{t e m p e r a t u r e}

$\frac{V_{1}}{V_{2}} = \sqrt{\frac{T_{1}}{T_{2}}}$

therefore, $\frac{360}{V_{2}} = \sqrt{\frac{27 + 273}{127 + 273}}$

$V_{2} = 240 \sqrt{3}$ m/s

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Current Electricity

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Question 27 Report

The most suitable type of mirror used for the construction of the search light is the

concave mirror

convex mirror

spherical mirror

parabolic mirror

Answer Details

The most suitable type of mirror used for the construction of a searchlight is the parabolic mirror. A parabolic mirror is a type of mirror that has a parabolic shape, meaning it is curved in such a way that it reflects incoming light rays to a single focal point. This makes it ideal for use in searchlights because it allows for the concentration of the light into a powerful beam that can be directed in a specific direction. On the other hand, convex mirrors diverge light rays, making them unsuitable for searchlights because they would disperse the light in different directions. Spherical mirrors, on the other hand, are not specifically designed to focus light to a single point, so they are less effective than parabolic mirrors for this purpose. Finally, while concave mirrors can focus light to a single point, they are not as effective as parabolic mirrors in doing so because they tend to produce more spherical aberration, which can distort the shape of the reflected image.

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Electrostatics

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Question 28 Report

A steel wire of length 0.50m is stretched between two fixed points and its fundamental frequency is 200Hz. The speed of the wave in the wire is

100ms-1

120ms-1

200ms-1

250ms-1

Answer Details

The speed of a wave in a stretched string is given by the formula v = √(F/μ), where v is the speed of the wave, F is the tension in the string, and μ is the linear mass density of the string (mass per unit length). The fundamental frequency of a stretched string is given by the formula f = (1/2L)√(F/μ), where L is the length of the string. In this question, we are given the length of the steel wire (L = 0.50m) and its fundamental frequency (f = 200Hz). We are asked to find the speed of the wave in the wire. Using the formula for the fundamental frequency, we can rearrange it to find the tension in the string: F = (4L^2μf^2) Substituting this expression for F into the formula for the wave speed, we get: v = √((4L^2μf^2)/μ) v = 2Lf Substituting the values given in the question, we get: v = 2(0.50m)(200Hz) = 200m/s Therefore, the speed of the wave in the wire is 200 m/s. The correct option is (c): 200ms^-1.

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Measurements And Units

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Question 29 Report

In free fall, a body of mass 1kg drops from a height of 125m from rest in 5s. How long will it take another body of mass 2kg to fall from rest from the same height? [g = 10ms-1·]

5s

10s

12s

15s

Answer Details

The time taken for an object to fall from a given height in free fall depends only on the height and the acceleration due to gravity. It is independent of the mass of the object. The formula for the time taken for an object to fall from rest from a height h in free fall is given by: t = √(2h/g) where h is the height and g is the acceleration due to gravity. In this question, we are given that a body of mass 1 kg falls from a height of 125 m in 5 s. Using the formula above, we can find the value of g: t = √(2h/g) 5 s = √(2 x 125 m / g) 25 s^2 = 250 m / g g = 250 m / (25 s^2) g = 10 m/s^2 We are then asked to find how long it will take for a body of mass 2 kg to fall from rest from the same height. Using the same formula as before, but with the new value of g, we get: t = √(2h/g) t = √(2 x 125 m / 10 m/s^2) t = √(25) t = 5 s Therefore, it will take the body of mass 2 kg the same amount of time as the body of mass 1 kg to fall from the same height, which is 5 s. The correct option is (a): 5s.

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Motion

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Question 30 Report

The linear expansivity of brass is 2 x 10-5C-1. If the volume of a piece of brass is 15.00cm3 at 00C, What is the volume at 100oC?

16.03cm3

16.00cm3

15.09cm3

15cm3

Answer Details

linear expansivity =

\frac{V_{2} - V_{1}}{V_{1} \times Δ θ}

3 x 2 x 10-5 = $\frac{V_{2} - 15}{15 \times (100 - 0)}$

V2 = 15.09cm3

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Temperature And Its Measurement

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Question 31 Report

An object 0 lies at a distance m in front of concave mirror of focal length f. If m < f, then the final image obtained will be

virtual and diminished

magnified and erect

real and inverted

diminished and erect

Electrostatics

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Question 32 Report

A ball of mass 0.15kg is kicked against a rigid vertical wall with a horizontal velocity of 50ms-1. If it rebounced with a horizontal velocity of 30ms-1, Calculate the impulse of the ball on the ball · ·

3.0Ns

4.5Ns

7.5Ns

12.0Ns

Answer Details

Impulse = m(v-u)

= 0.15(80-50)

= 4.5N/s

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Work, Energy And Power

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Question 33 Report

A uniform meter rule weighing 0.5N is to be pivoted on a knife-edge at the 30cm-mark. where will a force of 2N be placed from the pivot to balance the meter rule?

95cm

25cm

20cm

5cm

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Question 34 Report

A 500W heater is used to heat 0.6kg of water from $25^\circ\mathrm{C}$ to $100^\circ\mathrm{C}$ in $t_2$ seconds. If another 1000W heater is used to heat 0.2kg of water from $10^\circ\mathrm{C}$ to $100^\circ\mathrm{C}$ in t, seconds, find $\frac{t_1}{t_2}$

50

5

5/4

1/5

Answer Details

Heat energy = Electrical energy

mc $θ$ = power x time

0.6 x c x (100 - 25) = 500 x t1

and, 0.2 x c x (100 - 10)= 100 x t2
$\frac{t_{1}}{t_{2}}$ = 5

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Heat Energy

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Question 35 Report

The electrochemical equivalent of a metal is 1.3 x 10-7kgC-1. The mass of the metal which 2.0 x 104C of electricity will deposit from a suitable electrolyte is

6.5 x 10-2kg

2.6 x 10-2kg

6.5 x 10-3kg

2.6 x 10-3kg

Answer Details

The electrochemical equivalent of a metal is the amount of the metal deposited per unit charge passed through an electrolyte. In this case, the electrochemical equivalent of the metal is given as 1.3 x 10^-7 kgC^-1. To find the mass of the metal deposited by 2.0 x 10^4 C of electricity, we can use the formula: mass = (charge x electrochemical equivalent) Substituting the values given, we get: mass = (2.0 x 10^4 C) x (1.3 x 10^-7 kgC^-1) = 2.6 x 10^-3 kg Therefore, the mass of the metal deposited by 2.0 x 10^4 C of electricity is 2.6 x 10^-3 kg. So, the correct option is: 2.6 x 10-3kg.

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Electric Cells

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Question 36 Report

How many grams of water at 17oC must be added to 42g of ice at 0oC to melt the ice completely? [specific latent heat of fusion of ice = 3.4 x 105Jkg-1, specific heat capacity of water = 4200Jkg-1k-1]

200g

300g

320g

400g

Answer Details

Heat lost = Heat gained

mc $θ$ = mL

m x 4200 x 17 = 42 x 3.4 x 105

therefore, m = 200g

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Quantity Of Heat

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Question 37 Report

The displacement d produced in a glass block of thickness t and refractive index n when an object is viewed through it is

t – n

t (1 + 1/n)

t (1-1/n)

t (1/n - 1)

Answer Details

When light passes through a medium with a different refractive index, it changes its direction. This effect is known as refraction. The amount of bending that occurs depends on the angle of incidence and the refractive indices of the two media involved. In this case, we are looking at the displacement produced in a glass block of thickness t and refractive index n when an object is viewed through it. The amount of displacement (d) can be calculated using the formula: d = t (1 - 1/n) Where t is the thickness of the glass block and n is the refractive index of the glass. Therefore, the correct option is (C), which gives the displacement as t (1 - 1/n).

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Refraction Of Light Through Plane And Curved Surfaces

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Question 38 Report

The physical quantity that has the same dimensions as impulse is

energy

momentum

surface tension

pressure

Answer Details

The physical quantity that has the same dimensions as impulse is momentum. Impulse is defined as the change in momentum of an object over a certain period of time. Momentum, on the other hand, is the product of an object's mass and its velocity. The dimensions of momentum are given by the product of the dimensions of mass and velocity, which are respectively [M] and [L]/[T]. Therefore, the dimensions of momentum are [M][L]/[T]. Similarly, the dimensions of impulse are also given by the product of the dimensions of force and time, which are respectively [M][L]/[T]^2 and [T]. Thus, the dimensions of impulse are [M][L]/[T]. Since momentum and impulse have the same dimensions of [M][L]/[T], we can say that they have the same physical quantity. In other words, the units used to measure momentum and impulse are interchangeable, which means that they are related to each other in a very fundamental way.

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Work, Energy And Power

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Question 39 Report

A parachute attains a terminal velocity when

its density is equal to the density of air

the viscous force of the air and the upthrust completely counteract its weight

it expands as a result of reduced external pressure

the viscous force of the air is equal to the sum of the weight and upthrust

Answer Details

When an object is dropped from a height, it experiences two forces: the force of gravity, which pulls the object down, and the air resistance, which pushes the object up. As the object falls faster, the air resistance also increases until it reaches a point where the two forces are equal and opposite. At this point, the net force on the object becomes zero and it stops accelerating. This is called the terminal velocity. A parachute works by increasing the air resistance on the person wearing it. When the parachute is deployed, it catches the air and creates a large surface area. This causes the air resistance to increase, slowing down the person's descent. Eventually, the air resistance becomes large enough to balance the force of gravity on the person, and they reach their terminal velocity. Therefore, the correct answer to the question is that a parachute attains a terminal velocity when the viscous force of the air and the upthrust completely counteract its weight. Answer "the viscous force of the air and the upthrust completely counteract its weight," is the correct answer.

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Read lesson note on Equilibrium Of Forces (WAEC)

Equilibrium Of Forces

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Question 40 Report

A bullet fired at a wooden block of thickness 0.15m manages to penetrate the block. If the mass of the bullet is 0.025kg and the average resisting force of the wood is 7.5 x 103N, calculate the speed of the bullet just before it hits the wooden block.

450ms-1

400ms-1

300ms-1

250ms-1

Answer Details

The work done by the resisting force of the wooden block is equal to the kinetic energy of the bullet just before it hits the wooden block. Therefore, we can equate the work done by the resisting force to the kinetic energy of the bullet: Work done = Force x distance = average resisting force x thickness of the block Kinetic energy of the bullet = (1/2) x mass x velocity^2 Since the bullet manages to penetrate the wooden block, we can assume that all its kinetic energy is used up in overcoming the resisting force of the wooden block. Therefore, we can equate the two expressions: (1/2) x mass x velocity^2 = average resisting force x thickness of the block Substituting the given values, we get: (1/2) x 0.025 x velocity^2 = 7.5 x 10^3 x 0.15 Simplifying this equation, we get: velocity^2 = (2 x 7.5 x 10^3 x 0.15) / 0.025 velocity^2 = 90,000 Taking the square root of both sides, we get: velocity = 300 m/s Therefore, the speed of the bullet just before it hits the wooden block is 300m/s. So the answer is from the given options.

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Current Electricity

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Question 41 Report

A ball is moving at 18ms-1 in a direction inclined at 60o to the horizontal. The horizontal component to its velocity is

9√3ms-1 ·

6√3ms-1 ·

8√3ms-1 ·

9ms-1

Motion

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Question 42 Report

Which of the following are true about the infra-red radiation? i. it is invisible ii. it is called heat ray iii. its frequency is higher than that of blue light iv. it travels as a transverse wave

i, ii, iii and iv

i, ii, iv only

i, iii, iv only

ii, iii, iv only

Answer Details

The correct option is: i, ii, iv only Infrared radiation is a type of electromagnetic radiation that has a longer wavelength than visible light, and therefore it is invisible to the human eye. It is commonly known as heat radiation because it is associated with the heat energy that objects emit. Infrared radiation is a type of electromagnetic radiation, and like all electromagnetic radiation, it travels as a transverse wave, which means that the oscillations of the electric and magnetic fields are perpendicular to the direction of the wave's propagation. The statement "its frequency is higher than that of blue light" is incorrect. In fact, the frequency of infrared radiation is lower than that of blue light.

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Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum

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Question 43 Report

In the AC circuit diagram above, the resonance frequency is

5000π Hz

2500π Hz

5000/π Hz

2500/π Hz

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Question 44 Report

A transformer which can produce 8V from a 240v a.c. supply, has an efficiency of 80%. If the current in the secondary coil is 15A, calculate the current in the primary coil.

0.625A

1.600A

2.500A

6.250A

Answer Details

To solve this problem, we can use the formula for power: Power (in watts) = Voltage x Current Since the transformer has an efficiency of 80%, it means that 80% of the input power is transferred to the output. The remaining 20% is lost as heat. Therefore, we can say that: Output Power = Input Power x Efficiency We know the output voltage is 8V, and the output current is 15A. So, the output power can be calculated as: Output Power = 8V x 15A = 120W Substituting the values in the formula for efficiency, we get: 120W = Input Power x 0.80 Input Power = 120W/0.80 = 150W Now, we can calculate the input current using the formula: Input Power = Input Voltage x Input Current Substituting the values, we get: 150W = 240V x Input Current Input Current = 150W/240V = 0.625A Therefore, the current in the primary coil is 0.625A.

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Question 45 Report

The tendon in a man's leg is 0.01m long. If a force of 5N stretches the tendon by 2.0 x 10-5m, calculate the strain on the muscle.

5 x 106

5 x 102

2 x 10-3

2 x 10-7

Answer Details

To calculate the strain on the muscle, we can use the formula: Strain = (Change in length) / (Original length) Here, the change in length is the amount by which the tendon is stretched, and the original length is the length of the tendon before it is stretched. Substituting the values, we get: Strain = (2.0 x 10^-5 m) / (0.01 m) Strain = 2.0 x 10^-5 / 0.01 Strain = 2.0 x 10^-5 x 100 Strain = 2.0 x 10^-3 So, the strain on the muscle is 2.0 x 10^-3. Therefore, the correct option is: "2 x 10^-3."

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Elasticity

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Question 46 Report

In a resonance tube experiment, if the fundamental frequency of the vibrating air column is 280Hz, the frequency of the third overtone is

70Hz

840Hz

1120Hz

1960Hz

Answer Details

F3 = 7Fo

= 7 x 280

= 1960Hz

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Electrostatics

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