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Question 1 Report
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Question 2 Report
F = m(V2−U2)2X
= 0.04(5002−02)2×50
F = 100N
Question 4 Report
In fig 3, three forces F1, F2, and F3 acting at O are in equilibrium. If the magnitude of F1 is 10N,and the magnitude of F2 is 5N, find the magnitude of F3
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Question 8 Report
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Question 10 Report
Question 11 Report
V = 0ms-1 at greatest height
S = u22g
Question 12 Report
Total time = 320320 = 1s
F = 11 = 11
= 1Hz
Question 13 Report
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Question 14 Report
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Question 15 Report
In fig 6, a ray of light in air strikes a glass plate at an angle of incidence 60 degrees, the reflected ray is observed to be perpendicular to the refracted ray, what is the refractive index of the glass
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Question 16 Report
Question 17 Report
Fig 1 is a graph of force against extension for a spiral spring, the force constant of the spring is given by the
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Question 18 Report
If the fig above E is an accumulator with negligible internal resistance. and the EMF 9.0V, The the total current is
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Question 19 Report
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Question 20 Report
Fig 4 represents a block-and-tackle pulley system on which an effort of W newtons supports a load of 120.0N if the efficiency of the system is 40% then the value of W is
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Question 21 Report
30027+273 = V254+273
V2 = 327cm3
Question 22 Report
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Question 23 Report
F = uvu+v
= 2×82+8
= 1.6cm
r = 2F
= 2 x 1.6
= 3.2cm
Question 24 Report
mq = 2mp
Cp X mp X θ p = Cq x mq x θ q
CpmqθqCqmpθq = θq×2mp2θqmp
CpCq = 22
Question 25 Report
In an experiment in which molten naphthalene is allowed to cool, the cooling curve in fig 5 was obtained, the temperature \(80^\circ C\) is known as
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Question 31 Report
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Question 33 Report
mass = V x D = 24 x 103
F = mg
= 24 x 103 x 10
= 24 x 104
Question 34 Report
= 2010
= 2cm ; distance between adjacent nodes
Question 35 Report
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Question 37 Report
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Question 38 Report
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Question 39 Report
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Question 40 Report
A uniform meter rule QR is balanced on a knife edge which is 55cm from R, when a mass of 10g is hung at P as shown above, the mass of the meter rule is (Note that QP is 10cm)
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Question 41 Report
Question 42 Report
= 3×108400×109
= 75 x 1015Hz
Question 43 Report
F = uvu+v
12 = u×3uu+3v
u = 16cm, and v = 48cm
therefore, distance between u and v
v = 48 - 16 = 32cm
Question 44 Report
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Question 45 Report
i = sin-111?5
= sin-11015
= sin-123
Question 46 Report
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