To what temperature must a gas be raised from 273K in order to double both its volume and pressure?``

To double the pressure and volume of a gas, we need to use the combined gas law, which states that: (P1 × V1) / T1 = (P2 × V2) / T2 where P is the pressure, V is the volume, and T is the temperature of the gas. Let's assume that the initial temperature, pressure, and volume of the gas are T1 = 273 K, P1 = 1 atm, and V1 = 1 L, respectively. If we want to double both the pressure and volume of the gas, then the final values will be P2 = 2 atm and V2 = 2 L. Substituting these values into the combined gas law, we get: (1 atm × 1 L) / 273 K = (2 atm × 2 L) / T2 Solving for T2, we get: T2 = (2 atm × 2 L × 273 K) / (1 atm × 1 L) = 1092 K Therefore, the gas must be raised to a temperature of 1092 K in order to double both its volume and pressure.