A cube of sides 0.1m hangs freely from a string. What is the upthrust on the cube when totally immersed in water? [density of water is 1000kgm-2, g = 10ms-2...
Question 1 Report
A cube of sides 0.1m hangs freely from a string. What is the upthrust on the cube when totally immersed in water? [density of water is 1000kgm-2, g = 10ms-2]
Answer Details
When an object is submerged in a fluid, it experiences an upward force called buoyant force or upthrust. The magnitude of this force is equal to the weight of the fluid displaced by the object. In this problem, the cube has a volume of (0.1m)^3 = 0.001m^3. When the cube is immersed in water, it displaces an equal volume of water. Using the density of water, we can calculate the mass of the displaced water as: mass = density x volume = 1000kg/m^3 x 0.001m^3 = 1kg The weight of the displaced water is: weight = mass x gravitational acceleration = 1kg x 10m/s^2 = 10N Therefore, the upthrust on the cube is 10N. Therefore, the correct option is 10 N.
Download The App On Google Playstore
Everything you need to excel in your exams
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning