Two 50 \(\mu\) Farad parallel plate capacitors are connected in series. The combined capacitor is then connected across a 100-V battery. The charge on each ...
Question 1 Report
Two 50 \(\mu\) Farad parallel plate capacitors are connected in series. The combined capacitor is then connected across a 100-V battery. The charge on each plate of the
Answer Details
When capacitors are connected in series, the total capacitance decreases. The formula for calculating the total capacitance of capacitors connected in series is:
1/C_total = 1/C1 + 1/C2 + 1/C3 + ...
where C1, C2, C3, ... are the capacitances of each capacitor.
In this problem, two capacitors with capacitance 50 microFarads are connected in series. Using the formula above, we can calculate the total capacitance:
1/C_total = 1/C1 + 1/C2
1/C_total = 1/50 microF + 1/50 microF
1/C_total = 2/50 microF
C_total = 25 microF
Now, we can use the formula for capacitance to calculate the charge on each plate of the combined capacitor when it is connected to a 100-V battery:
Q = C * V
Q = 25 microF * 100 V
Q = 2.5 x 10^-3 C
Therefore, the charge on each plate of the combined capacitor is 2.5 x 10^-3 C. Option (B) is the closest answer, which is 2.50 x 10^-3 C.
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