A load of 20N on a wire of cross-sectional area 8 x 10-7m2, produces an extension of 10m2. calculate Young's modulus for the material of the wire if its len...
Question 1 Report
A load of 20N on a wire of cross-sectional area 8 x 10-7m2, produces an extension of 10m2. calculate Young's modulus for the material of the wire if its length is 3m
Answer Details
Young's modulus is defined as the ratio of stress to strain in a material under tensile load. In this problem, the load on the wire is 20N, the extension produced is 10^(-2)m and the cross-sectional area is 8 x 10^(-7) m^2. From the given information, we can calculate the stress in the wire using the formula: stress = load / area Therefore, stress = 20N / (8 x 10^(-7) m^2) = 2.5 x 10^7 N/m^2 We can also calculate the strain using the formula: strain = extension / original length Here, the extension is 10^(-2)m and the original length is 3m. Therefore, the strain is: strain = 10^(-2)m / 3m = 3.33 x 10^(-3) Now, we can use the definition of Young's modulus: Young's modulus = stress / strain Substituting the values we calculated above, we get: Young's modulus = (2.5 x 10^7 N/m^2) / (3.33 x 10^(-3)) = 7.5 x 10^10 N/m^2 Therefore, the answer is:
7.5 x 1011Nm-2
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