The diagram is a circle with centre O. Find the area of the shaded portion.
Answer Details
To find the area of the shaded portion, we need to subtract the area of the triangle from the area of the sector.
First, we need to find the radius of the circle. Since the diameter is given as 6cm, the radius is half of it which is 3cm.
Next, we need to find the angle of the sector. We can do this by using the properties of the isosceles triangle. The angle at the centre of the circle is twice the angle at the circumference of the circle. So, the angle at the centre of the circle is:
2 x (180 - 90) = 180 degrees
This means that the angle of the sector is 180 degrees.
Now we can calculate the area of the sector:
Area of sector = (angle/360) x πr^2
= (180/360) x π(3)^2
= 4.5π cm^2
Next, we need to find the area of the triangle. Since the triangle is isosceles, the base angles are equal, and we can use trigonometry to find the height.
The base of the triangle is equal to the diameter of the circle which is 6cm.
Using trigonometry, we know that:
tan(45) = height/base
height = base x tan(45)
height = 6 x 1
height = 6cm
Now we can calculate the area of the triangle:
Area of triangle = (1/2) x base x height
= (1/2) x 6 x 6
= 18 cm^2
Finally, we can calculate the area of the shaded portion by subtracting the area of the triangle from the area of the sector:
Area of shaded portion = Area of sector - Area of triangle
= 4.5π - 18
= (9/2)(π - 2) cm^2
Therefore, the answer is 9(π−2)cm2.