What is the value of n in the following equation? Cr2O72- + 14H+ + ne- → 2Cr 3+ + 7H2O

Assessment: WAEC SSCE - Chemistry - 2011 (Objective) Subject: Chemistry

Question 1 Report

What is the value of n in the following equation? Cr2O72- + 14H+ + ne- → 2Cr 3+ + 7H2O
Answer Details
In the given chemical equation, the electrons (ne-) appear on the left-hand side of the equation as a reactant. This indicates that the equation is showing a reduction half-reaction, where electrons are gained. To balance the electrons gained in the reduction half-reaction, we need to identify the number of electrons that are being transferred. In this case, we can see that 6 electrons are being gained by the reactants (Cr2O72- and 14H+) to form 2 moles of Cr3+ and 7 moles of H2O. Therefore, the value of n in the equation is 6.
Read lesson note on Electrolysis (JAMB)
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