What is the amount of magnesium that would contain 1.20 x 1024 particles? [Mg = 24, Avogadro's constant = 6.02 x 1023]

Assessment: WAEC SSCE - Chemistry - 2011 (Objective) Subject: Chemistry

Question 1 Report

What is the amount of magnesium that would contain 1.20 x 1024 particles? [Mg = 24, Avogadro's constant = 6.02 x 1023]
Answer Details
Avogadro's constant is the number of particles in one mole of a substance, which is approximately equal to 6.02 x 10^23 particles. Therefore, if we have 1.20 x 10^24 particles of magnesium, we can calculate the number of moles by dividing the number of particles by Avogadro's constant: n = (1.20 x 10^24 particles) / (6.02 x 10^23 particles/mole) n = 2.0 moles Therefore, the amount of magnesium that would contain 1.20 x 10^24 particles is 2.0 moles. So, the correct option is "2.0 moles".

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