Factorize completely 4abx - 2axy -12b2x + 6bxy

Assessment: JAMB UTME - Mathematics - 2003 Subject: General Mathematics

Question 1 Report

Factorize completely 4abx - 2axy -12b2x + 6bxy
Answer Details
To factorize the given expression completely, we need to look for the common factors among the terms. First, we can take out 2 as a common factor from all the terms. So the expression becomes: 2(2abx - axy - 6b^2x + 3bxy) Next, we can take out ax as a common factor from the first two terms and 3bx as a common factor from the last two terms. So we get: 2ax(2b - y) - 3bx(2b - y) Now, we can see that (2b - y) is a common factor in both terms, so we can take it out. This gives us: (2b - y)(2ax - 3bx) So, the expression is completely factorized as (2b - y)(2ax - 3bx). Thus, the correct option is: 2x(a - 3b)(2b - y)

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