A ball is thrown vertically upwards with a velocity of 15\(ms^{-1}\). Calculate the maximum height reached. \([g = 10ms^{-2}]\)
Question 1 Report
A ball is thrown vertically upwards with a velocity of 15\(ms^{-1}\). Calculate the maximum height reached. \([g = 10ms^{-2}]\)
Answer Details
To solve this problem, we can use the formula:
\begin{align*}
h &= \frac{v_{0}^{2}}{2g}
\end{align*}
where h is the maximum height reached, \(v_{0}\) is the initial velocity and g is the acceleration due to gravity.
Substituting the given values, we get:
\begin{align*}
h &= \frac{(15\ ms^{-1})^{2}}{2(10\ ms^{-2})}\\
&= \frac{225\ m^{2}s^{-2}}{20\ m s^{-2}}\\
&= 11.25\ m
\end{align*}
Therefore, the maximum height reached by the ball is 11.25m.
Hence, the correct option is (c) 11.25m.
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