Find the distance between the points (2, 5) and (5, 9).

Assessment: WAEC SSCE - Further Mathematics - 2014 (Objective) Subject: Further Mathematics

Question 1 Report

Find the distance between the points (2, 5) and (5, 9).

Answer Details
To find the distance between two points in a plane, we can use the distance formula: $$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$$ where (x1, y1) and (x2, y2) are the coordinates of the two points. In this case, the given points are (2, 5) and (5, 9), so we can substitute the values into the formula: $$d = \sqrt{(5-2)^2 + (9-5)^2} = \sqrt{3^2 + 4^2} = \sqrt{9+16} = \sqrt{25} = 5$$ Therefore, the distance between the two points is 5 units. So, the answer is option (B).
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