Find the equation of a circle with centre (2, -3) and radius 2 units.

Assessment: WAEC SSCE - Further Mathematics - 2014 (Objective) Subject: Further Mathematics

Question 1 Report

Find the equation of a circle with centre (2, -3) and radius 2 units.

Answer Details
The equation of a circle with center (h,k) and radius r is given by the formula: $$(x-h)^2 + (y-k)^2 = r^2$$ In this case, the center of the circle is (2,-3) and the radius is 2 units. Therefore, we have: $$(x-2)^2 + (y+3)^2 = 2^2$$ Expanding the left-hand side, we get: $$x^2 - 4x + 4 + y^2 + 6y + 9 = 4$$ Simplifying this equation, we get: $$x^2 + y^2 - 4x + 6y + 9 = 0$$ Therefore, the equation of the circle is (A) \(x^{2} + y^{2} - 4x + 6y + 9 = 0\).

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