Integrate \((x - \frac{1}{x})^{2}\) with respect to x.

Integrate \((x - \frac{1}{x})^{2}\) with respect to x.

Answer Details

To integrate \((x-\frac{1}{x})^2\) with respect to x, we need to expand the square first: $$(x-\frac{1}{x})^2 = x^2 - 2 + \frac{1}{x^2}$$ Now we can integrate term by term: $$\int (x^2 - 2 + \frac{1}{x^2}) dx = \frac{x^3}{3} - 2x - \frac{1}{x} + c$$ where c is the constant of integration. Therefore, the answer is the option (D).