A particle accelerates at 12\(ms^{-2}\) and travels a distance of 250m in 6 seconds. Find the initial velocity of the particle.
Answer Details
We can use the equation:
distance = initial velocity × time + 0.5 × acceleration × time²
We are given the distance as 250m, the time as 6 seconds, and the acceleration as 12\(ms^{-2}\). We need to find the initial velocity.
Substituting the values we get,
250 = initial velocity × 6 + 0.5 × 12 × 6²
Simplifying,
250 = 6initial velocity + 216
250 - 216 = 6initial velocity
34 = 6initial velocity
initial velocity = 34/6 = 5.67 \(ms^{-1}\) (rounded to two decimal places)
Therefore, the initial velocity of the particle is 5.67 \(ms^{-1}\), which is option A.