Propane carbon(IV)oxide diffuse at the same rate because [H = 1.00, C = 12.0, O = 16.0]

Propane carbon(IV)oxide diffuse at the same rate because [H = 1.00, C = 12.0, O = 16.0]

Answer Details

The diffusion rate of a gas is directly proportional to its molecular mass. Propane (C3H8) has a higher molecular mass than carbon dioxide (CO2). However, since the question asks about carbon(IV)oxide (CO2), which has a molecular mass of 44, the answer is that propane and carbon(IV)oxide diffuse at the same rate because they have the same relative molecular mass. Therefore, "They have the same relative molecular mass" is the correct answer.