Given the inductor of inductance 5mH, 10mH and 20mH connected in series, the effective inductance is

Answer Details

When inductors are connected in series, the total inductance is the sum of the individual inductances. Therefore, the effective inductance of the inductors of inductance 5mH, 10mH, and 20mH connected in series is: Effective inductance = 5mH + 10mH + 20mH = 35mH So, the correct answer is 35.0mH. In summary, when inductors are connected in series, the total inductance is the sum of the individual inductances.