If a body mass 5kg is thrown vertically upwards with velocity u,at what height will the potential energy equal to the kinetic energy?

The correct answer is: h = (u)2/2g. When an object is thrown vertically upwards, it rises to a certain height, reaches its maximum height, and then falls back to the ground. At the maximum height, the potential energy of the object is equal to its kinetic energy. The potential energy of an object is given by the formula: P.E = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the ground. The kinetic energy of an object is given by the formula: K.E = (1/2)mu^2, where m is the mass of the object, and u is the velocity of the object. At the maximum height, the velocity of the object becomes zero. Therefore, we can equate the potential energy at the maximum height to the kinetic energy just before the object reached the maximum height. So, we have: P.E = K.E mgh = (1/2)mu^2 h = (1/2)u^2/g Substituting the given values, we get: h = (u)^2/2g Therefore, the height at which the potential energy of the object is equal to its kinetic energy is given by the formula: h = (u)^2/2g.