When a pure semiconductor is heated, its resistance

Answer Details

When a pure semiconductor is heated, its resistance decreases. This is because when the temperature of the semiconductor increases, the number of free electrons and holes also increases, which leads to an increase in the conductivity of the material. The increase in conductivity causes a decrease in the resistance of the semiconductor. The relationship between temperature and resistance of a semiconductor is described by the equation: R = Ro exp(T/Tref), where R is the resistance, Ro is the resistance at a reference temperature Tref, and T is the absolute temperature. Therefore, as the temperature increases, the value of R decreases.