A sealed flask contains 600cm3 of air at 27°C and is heated to 35°C at constant pressure. The new volume is?
Question 1 Report
A sealed flask contains 600cm3 of air at 27°C and is heated to 35°C at constant pressure. The new volume is?
Answer Details
To solve this problem, we can use Charles's law, which states that at constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature.
First, we need to convert the temperatures from Celsius to Kelvin by adding 273.15:
Initial temperature (in Kelvin) = 27 + 273.15 = 300.15 K
Final temperature (in Kelvin) = 35 + 273.15 = 308.15 K
Next, we can use the formula for Charles's law:
V1 / T1 = V2 / T2
where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.
We can rearrange this formula to solve for V2:
V2 = (V1 x T2) / T1
Plugging in the given values, we get:
V2 = (600 cm^3 x 308.15 K) / 300.15 K
V2 = 616 cm^3
Therefore, the new volume of the air in the flask is 616 cm^3.
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