Question 1 Report

A force F required to keep a 5 kg mass moving round a cycle of radius 3.5 m at a speed of 7 ms-1. What is the speed, if the force is tripled?

Answer Details

The force which is centripetal F = MV2_R =5 x 723.5 = 70 V = √(Fr) and if F is tripped, then V = √(3Fr)/m = √(3x70x3.5)/5 = 12.1ms-1