A force F required to keep a 5 kg mass moving round a cycle of radius 3.5 m at a speed of 7 ms-1. What is the speed, if the force is tripled?

A force F required to keep a 5 kg mass moving round a cycle of radius 3.5 m at a speed of 7 ms-1. What is the speed, if the force is tripled?

Answer Details

The force which is centripetal
F = MV2_R
=5 x 723.5
= 70
V = √(Fr) and if F is tripped, then
V = √(3Fr)/m
= √(3x70x3.5)/5
= 12.1ms-1