Given that 32.0g sulphur contains 6.02 x 10 23 sulphur atoms how many atoms are there in 2.70g of aluminium? {Al = 27, S =32}

The given information provides us with the number of atoms present in 32.0g of sulfur, which is 6.02 x 10^23 atoms. Now, we need to find out the number of atoms in 2.70g of aluminum, given that the atomic mass of aluminum is 27. To find the number of atoms in 2.70g of aluminum, we need to first calculate the number of moles of aluminum present in 2.70g. Number of moles = mass/molar mass Molar mass of aluminum = 27g/mol Number of moles of aluminum = 2.70g/27g/mol = 0.1mol Now, we can use Avogadro's number, which is the number of particles (atoms or molecules) in one mole of a substance, to calculate the number of atoms in 0.1mol of aluminum. Avogadro's number = 6.02 x 10^23 particles/mol Number of atoms in 0.1mol of aluminum = 0.1mol x 6.02 x 10^23 particles/mol = 6.02 x 10^22 atoms Therefore, the correct answer is 6.02 x 10^22.