For what value of x is the tangent to the curve y = x2 - 4x + 3 parallel to the x-axis?
Answer Details
To find the value of x for which the tangent to the curve y = x^2 - 4x + 3 is parallel to the x-axis, we need to find the point on the curve where the slope of the tangent line is zero.
The slope of the tangent to a curve y = f(x) at a point (a, f(a)) is given by f'(a), the derivative of f(x) evaluated at x = a.
So, we need to find the derivative of y = x^2 - 4x + 3, which is y' = 2x - 4.
Setting y' equal to zero, we get:
2x - 4 = 0
Solving for x, we get:
x = 2
Therefore, the value of x for which the tangent to the curve y = x^2 - 4x + 3 is parallel to the x-axis is 2.