2H2(g) + O2(g) → 2H2O(g) ΔH = -ve What happens to the equilibrium constant of the reaction above if the temperature is increased?

Question 1 Report

2H2(g) + O2(g) → 2H2O(g) ΔH = -ve

What happens to the equilibrium constant of the reaction above if the temperature is increased?

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