f 5.0 cm\(^-3\) of 0.200 mol dm(^-3\) Na\(_2\)CO\(_3\) was diluted to 250cm(^-3\) solution, what would be the concentration of the resulting solution?
Question 1 Report
f 5.0 cm\(^-3\) of 0.200 mol dm(^-3\) Na\(_2\)CO\(_3\) was diluted to 250cm(^-3\) solution, what would be the concentration of the resulting solution?
Answer Details
To find the concentration of the resulting solution after dilution, we need to calculate the amount of solute (Na_2CO_3) in the new solution. The concentration of a solution is given by the amount of solute per unit volume of the solution.
The dilution formula is:
C1 * V1 = C2 * V2
Where C1 is the initial concentration (0.200 mol dm^-3), V1 is the initial volume (5.0 cm^-3), C2 is the final concentration (what we are trying to find), and V2 is the final volume (250 cm^-3).
Plugging in the values:
0.200 * 5.0 = C2 * 250
0.200 * 5.0 / 250 = C2
C2 = 0.004 mol dm^-3
So, the concentration of the resulting solution is 0.004 mol dm^-3.
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