In a hydraulic press, the pump piston exerts a pressure of 100 pa on the liquid. what force is exerted in the second piston of cross sectional area 3 m2?

In a hydraulic press, the pump piston exerts a pressure of 100 pa on the liquid. what force is exerted in the second piston of cross sectional area 3 m2?

Answer Details

The hydraulic press works on the principle of Pascal's law, which states that the pressure applied at any point in an enclosed fluid is transmitted uniformly in all directions. In this case, the pump piston exerts a pressure of 100 Pa on the liquid. This pressure is transmitted through the liquid and acts equally in all directions, including on the second piston. The force exerted on the second piston can be calculated using the formula: Force = Pressure x Area where pressure is the pressure applied by the pump piston, and area is the cross-sectional area of the second piston. Substituting the values given in the question, we get: Force = 100 Pa x 3 m^2 Simplifying the equation, we get: Force = 300 N Therefore, the force exerted on the second piston is 300 N.