How much heat is absorbed when a block of copper of mass 0.05kg and specific heat capacity 390Jkg-1K-1 is heated from 20oC to 70oC?

Assessment: JAMB UTME - Physics - 1992 Subject: Physics

Question 1 Report

39 . 98 x 10-1J

9.75 x 102J

3.98 x 103J

9.75 x 103J

Answer Details

The amount of heat absorbed by the copper block can be calculated using the formula: Q = mcΔT where Q is the amount of heat absorbed, m is the mass of the block, c is the specific heat capacity of copper, and ΔT is the change in temperature. Substituting the given values, we have: Q = (0.05 kg)(390 J/kg.K)(70°C - 20°C) Q = (0.05 kg)(390 J/kg.K)(50°C) Q = 975 J Therefore, the amount of heat absorbed by the copper block is 975 J. So, the correct option is: - 9.75 x 102J

Read lesson note on Heat Energy (WAEC)

Heat Energy

View Answer

How much heat is absorbed when a block of copper of mass 0.05kg and specific heat capacity 390Jkg-1K-1 is heated from 20oC to 70oC?

Related Questions

Download The App On Google Playstore