RS(aq) + HF(aq) → RF(s) + HS(aq) ΔH = -65.7 kj mol(-1). From the equation above, it can be deduced that

Question 1 Report

RS(aq) + HF(aq) → RF(s) + HS(aq)

ΔH = -65.7 kj mol(-1).

From the equation above, it can be deduced that

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