90.0g of MgCI2 was placed in 50.0cm3 of water to give a saturated solubility of the salt is 8.0 mol dm3 at the same temperature, what is the mass of the sal...

90.0g of MgCI2 was placed in 50.0cm3 of water to give a saturated solubility of the salt is 8.0 mol dm3 at the same temperature, what is the mass of the salt left undissolved at the given temperature?(Mg = 24, Cl = 35.5)

Answer Details

The question is asking for the mass of MgCl2 left undissolved in water. We know that the solubility of the salt is 8.0 mol dm^3 at the given temperature, and we have 50.0 cm^3 of water. Therefore, the maximum amount of MgCl2 that can dissolve in the water is: 8.0 mol/dm^3 x 0.050 dm^3 = 0.40 mol The molar mass of MgCl2 is: 24.3 + (2 x 35.5) = 95.3 g/mol So, the mass of MgCl2 that can dissolve in the water is: 0.40 mol x 95.3 g/mol = 38.12 g Therefore, the mass of MgCl2 left undissolved is: 90.0 g - 38.12 g = 51.88 g, which can be rounded to 52.0 g. So the answer is: 52.0g