90.0g of MgCI2 was placed in 50.0cm3 of water to give a saturated solubility of the salt is 8.0 mol dm3 at the same temperature, what is the mass of the sal...
Question 1 Report
90.0g of MgCI2 was placed in 50.0cm3 of water to give a saturated solubility of the salt is 8.0 mol dm3 at the same temperature, what is the mass of the salt left undissolved at the given temperature?(Mg = 24, Cl = 35.5)
Answer Details
The question is asking for the mass of MgCl2 left undissolved in water. We know that the solubility of the salt is 8.0 mol dm^3 at the given temperature, and we have 50.0 cm^3 of water. Therefore, the maximum amount of MgCl2 that can dissolve in the water is:
8.0 mol/dm^3 x 0.050 dm^3 = 0.40 mol
The molar mass of MgCl2 is:
24.3 + (2 x 35.5) = 95.3 g/mol
So, the mass of MgCl2 that can dissolve in the water is:
0.40 mol x 95.3 g/mol = 38.12 g
Therefore, the mass of MgCl2 left undissolved is:
90.0 g - 38.12 g = 51.88 g, which can be rounded to 52.0 g.
So the answer is: 52.0g
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