Question 1 Report
0.05 mol dm-3 HCl is neutralized by 25 cm3 NaOH. If the volume of acid used is 32.00cm3, what is the concentration of the base
Answer Details
HCl + NaOH → NaCl + H2O CAVA = NA/NB = (0.05 * 32)/(CB * 25) ∴ CB = (0.05 * 32)/25 = 0.064 mol dm-3