How many atoms are present in 6.0g of magnesium? [Mg = 24, NA = 6.02 x 1023 mol-1]

Answer Details

6.0 grams of magnesium contains 1.51 x 10^23 atoms of magnesium. This can be calculated using the following steps: 1. Determine the number of moles of magnesium present in 6.0 grams using the formula: moles = mass/molar mass 2. The molar mass of magnesium is 24 g/mol 3. So, 6.0 g / 24 g/mol = 0.25 moles of magnesium 4. Using Avogadro's number (6.02 x 10^23 atoms/mol), we can determine the number of atoms of magnesium present: 5. 0.25 moles * 6.02 x 10^23 atoms/mol = 1.51 x 10^23 atoms. Therefore, 6.0 grams of magnesium contains 1.51 x 10^23 atoms of magnesium.