If the decay constant of a radioactive substance is 0.231s1, the half-life is?

Answer Details

The decay constant of a radioactive substance is defined as the probability of decay per unit time. The half-life of a substance is defined as the time it takes for half of the initial quantity of the substance to decay. The relationship between the decay constant (λ) and the half-life (t_{1/2}) is given by: t_{1/2} = ln(2) / λ where ln(2) is the natural logarithm of 2, which is approximately 0.693. Substituting the given value of the decay constant (λ = 0.231 s^{-1}) into the above equation gives: t_{1/2} = ln(2) / 0.231 s^{-1} ≈ 3.00 s Therefore, the half-life of the substance is approximately 3.00 seconds. So, the correct option is: 3.00 s.