If a load of mass 10N stretched a cord by 1.2cm, what is the total work done?

Answer Details

The work done is calculated as the product of the force applied and the displacement caused in the direction of the force. In this case, the force applied is the weight of the load, which is equal to mass times acceleration due to gravity (10N = 10 kg x 9.8 m/s^2 = 98 N), and the displacement caused is the extension of the cord, which is 1.2 cm = 0.012 m.
Therefore, the work done is W = F x d = 98 N x 0.012 m = 1.176 J.
Rounding off to two significant figures, the answer is 1.2 x 10^-2 J, which corresponds to 6.0 x 10^-2 J.