A near sighted student has a near point of 0.1m and a focal length of 5.0cm. What is the student's far point?
Question 1 Report
A near sighted student has a near point of 0.1m and a focal length of 5.0cm. What is the student's far point?
Answer Details
A nearsighted person can see nearby objects clearly but has trouble seeing objects that are far away. The near point is the closest point at which a person can see an object clearly, and the far point is the farthest point at which a person can see an object clearly.
The formula for calculating the far point of a nearsighted person is given by:
far point = (1 / near point) + (1 / focal length)
where the near point and focal length are given in meters.
In this problem, we are given that the near point is 0.1 m and the focal length is 5.0 cm. We need to convert the focal length to meters by dividing by 100:
focal length = 5.0 cm / 100 = 0.05 m
Substituting the values into the formula for far point, we get:
far point = (1 / 0.1 m) + (1 / 0.05 m) = 10 m + 20 m = 30 m
Therefore, the far point of the student is 30 m.
None of the given options match the correct answer, so the answer is "No Correct Option."
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