A force of 200N acting on a body of mass 20kg initially at rest causes it to move a distance of 320m along a straight line for t secs. Find the value of t.
A force of 200N acting on a body of mass 20kg initially at rest causes it to move a distance of 320m along a straight line for t secs. Find the value of t.
Answer Details
To solve this problem, we can use the kinematic equation:
s = ut + (1/2)at^2
where s is the distance travelled, u is the initial velocity (0 in this case), a is the acceleration, and t is the time taken.
We can rearrange this equation to solve for t:
t = sqrt((2s)/a)
where sqrt() means "square root of".
In this case, the force of 200N causes an acceleration of:
a = F/m = 200/20 = 10 m/s^2
And the distance travelled is given as 320m.
Plugging in the values, we get:
t = sqrt((2s)/a) = sqrt((2 * 320)/10) = sqrt(64) = 8s
Therefore, the value of t is 8s, which is.