The force of attraction between two point masses is 10-4N when the distance between them is 0.18m. If the distance is reduced to 0.06m, calculate the force.
The force of attraction between two point masses is 10-4N when the distance between them is 0.18m. If the distance is reduced to 0.06m, calculate the force.
Answer Details
The force of attraction between two point masses is given by the equation:
F = G * (m1 * m2) / r^2
where F is the force of attraction, G is the gravitational constant, m1 and m2 are the masses of the two point masses, and r is the distance between them.
In this case, we know that the force of attraction between the two point masses is 10^-4 N when the distance between them is 0.18m. We can use this information to find the value of G * (m1 * m2):
G * (m1 * m2) = F * r^2
G * (m1 * m2) = (10^-4 N) * (0.18 m)^2
G * (m1 * m2) = 3.24 x 10^-6 N m^2
Now, if the distance between the two point masses is reduced to 0.06m, we can use the same equation to find the new force of attraction:
F = G * (m1 * m2) / r^2
F = (G * (m1 * m2) / (0.06 m)^2
F = (3.24 x 10^-6 N m^2) / (0.06 m)^2
F = 9 x 10^-4 N
Therefore, the force of attraction between the two point masses is 9 x 10^-4 N when the distance between them is reduced to 0.06m.
So the correct option is: 9.0 x 10^-4 N