The force of attraction between two point masses is 10-4N when the distance between them is 0.18m. If the distance is reduced to 0.06m, calculate the force.

The force of attraction between two point masses is given by the equation: F = G * (m1 * m2) / r^2 where F is the force of attraction, G is the gravitational constant, m1 and m2 are the masses of the two point masses, and r is the distance between them. In this case, we know that the force of attraction between the two point masses is 10^-4 N when the distance between them is 0.18m. We can use this information to find the value of G * (m1 * m2): G * (m1 * m2) = F * r^2 G * (m1 * m2) = (10^-4 N) * (0.18 m)^2 G * (m1 * m2) = 3.24 x 10^-6 N m^2 Now, if the distance between the two point masses is reduced to 0.06m, we can use the same equation to find the new force of attraction: F = G * (m1 * m2) / r^2 F = (G * (m1 * m2) / (0.06 m)^2 F = (3.24 x 10^-6 N m^2) / (0.06 m)^2 F = 9 x 10^-4 N Therefore, the force of attraction between the two point masses is 9 x 10^-4 N when the distance between them is reduced to 0.06m. So the correct option is: 9.0 x 10^-4 N