Find the direction cosines of the vector \(4i - 3j\).

Assessment: WAEC SSCE - Further Mathematics - 2010 (Objective) Subject: Further Mathematics

Question 1 Report

Find the direction cosines of the vector \(4i - 3j\).

Answer Details
Direction cosines are the cosines of the angles that a vector makes with the positive x, y and z axes. Let's denote the vector by \(\mathbf{v} = 4\mathbf{i} - 3\mathbf{j} + 0\mathbf{k}\). Then the direction cosines of \(\mathbf{v}\) are: \begin{align*} \cos\alpha &= \frac{4}{5} \\ \cos\beta &= \frac{-3}{5} \\ \cos\gamma &= 0 \end{align*} Therefore, the correct option is: - \(\frac{4}{5}, -\frac{3}{5}\)

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