The third of geometric progression (G.P) is 10 and the sixth term is 80. Find the common ratio.

Assessment: WAEC SSCE - Further Mathematics - 2010 (Objective) Subject: Further Mathematics

Question 1 Report

The third of geometric progression (G.P) is 10 and the sixth term is 80. Find the common ratio.

Answer Details
We can use the formula for the nth term of a geometric progression to solve this problem. Let a be the first term and r be the common ratio, then the third term is ar^2 and the sixth term is ar^5. We are given that ar^2 = 10 and ar^5 = 80. Dividing the second equation by the first, we get: (ar^5)/(ar^2) = 80/10 Simplifying and canceling a, we get: r^3 = 8 Taking the cube root of both sides, we get: r = 2 Therefore, the common ratio is 2, and the answer is (a) 2.
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