If the quantity of oxygen occupying 2.76L container at a pressure of 0.825 atm and 300k is reduced by one-half, what is the pressure exerted by the remainin...

If the quantity of oxygen occupying 2.76L container at a pressure of 0.825 atm and 300k is reduced by one-half, what is the pressure exerted by the remaining gas?

Answer Details

Using the combined gas law formula,

Given that P${}_1$ = 0.825,   V${}_1$ = 2.76 L, V${}_2$ = 1.38 L, P${}_2$ = ?

And T1 = T2; we would have P${}_2$ = [ P${}_1$ X V${}_1$ ] / V${}_2$

: [0.825 X 2.76] / 1.38

= 1.650atm