Question 1 Report

A constant force of 40N acting on a body initially at rest gives an acceleration of 0.1ms-2 for 4s. Calculate the work done by the force

Answer Details

X = ut + 12 $\frac{1}{2}$at2

= (0 x 4) + (12 $\frac{1}{2}$ x 0.1 x 4 x 4)

= 0.8m

workdone = force x distance

= 40 x 0.8

= 32J