The sine, cosine and tangent of 210o are respectively

Assessment: JAMB UTME - Mathematics - 1987 Subject: General Mathematics

Question 1 Report

\frac{1}{2}

\frac{\sqrt{3}}{2}

\frac{\sqrt{3}}{2}

\frac{1}{2}

\frac{\sqrt{3}}{2}

\frac{\sqrt{3}}{3}

\frac{1}{2}

\frac{\sqrt{3}}{2}

\frac{\sqrt{3}}{2}

$\frac{- 1}{2}$ , $\frac{\sqrt{- 3}}{2}$ , $\frac{\sqrt{3}}{3}$

$\frac{\sqrt{3}}{3}$

Answer Details

210o = 180o - 210o = 30o
From ratio of sides, sin -30o = - $\frac{1}{2}$
Cos 210o = 180o - 210o = -30o
= cos -30o = $\frac{- 3}{2}$
But tan 30o = $\frac{1}{3}$ , rationalizing this
= $\frac{1}{3}$ x $\frac{3}{3}$ = $\frac{3}{3}$
∴ = $\frac{- 1}{2}$ , $\frac{\sqrt{- 3}}{2}$ , $\frac{\sqrt{3}}{3}$

Read lesson note on Sine, Cosine And Tangent Of An Angle (WAEC)

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Sine, Cosine And Tangent Of An Angle

Trigonometry

Coordinate Geometry

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The sine, cosine and tangent of 210o are respectively

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