The sine, cosine and tangent of 210o are respectively

Assessment: JAMB UTME - Mathematics - 1987 Subject: General Mathematics

Question 1 Report

\frac{1}{2}

\frac{\sqrt{3}}{2}

\frac{\sqrt{3}}{2}

\frac{1}{2}

\frac{\sqrt{3}}{2}

\frac{\sqrt{3}}{3}

\frac{1}{2}

\frac{\sqrt{3}}{2}

\frac{\sqrt{3}}{2}

$\frac{- 1}{2}$ , $\frac{\sqrt{- 3}}{2}$ , $\frac{\sqrt{3}}{3}$

$\frac{\sqrt{3}}{3}$

Answer Details

210o = 180o - 210o = 30o
From ratio of sides, sin -30o = -

\frac{1}{2}

Cos 210o = 180o - 210o = -30o
= cos -30o =

\frac{- 3}{2}

But tan 30o =

\frac{1}{3}

, rationalizing this
=

\frac{1}{3}

\frac{3}{3}

\frac{3}{3}

∴ =

\frac{- 1}{2}

\frac{\sqrt{- 3}}{2}

\frac{\sqrt{3}}{3}

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