An elastic string of force constant 200N m-1 is stretched through 0.8m within its elastic limit. Calculate the energy stored in the string
Question 1 Report
An elastic string of force constant 200N m-1 is stretched through 0.8m within its elastic limit. Calculate the energy stored in the string
Answer Details
The energy stored in an elastic string that is stretched is given by the equation:
E = 0.5kx²
where E is the energy stored, k is the force constant of the string, and x is the displacement from its original length.
In this case, the force constant k is given as 200 N/m, and the displacement x is 0.8 m.
Substituting these values in the above equation, we get:
E = 0.5 × 200 N/m × (0.8 m)²
E = 0.5 × 200 N/m × 0.64 m²
E = 64 J
Therefore, the energy stored in the elastic string is 64J.
Hence, the correct option is (a) 64.0J.
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