When a metal ball is heated through 30oC,its volume becomes 1.0018cm3. If the linear expansivity of the material of the ball is 2.0 x 10-5 K-1, calculate it...

Assessment: WAEC SSCE - Physics - 2004 (Objective) Subject: Physics

Question 1 Report

When a metal ball is heated through 30^oC,its volume becomes 1.0018cm³. If the linear expansivity of the material of the ball is 2.0 x 10^-5 K^-1, calculate its original volume

1.0000cm³

1.0020cm³

1.0036cm³

1.0180cm³

Answer Details

When a material is heated, it expands due to increase in temperature. The amount of expansion depends on the linear expansivity of the material which is the fractional increase in length per degree rise in temperature. Let V₀ be the original volume of the ball and ΔT = 30°C be the temperature rise. Then, the new volume V after heating is given by: V = V₀(1 + γΔT) where γ is the linear expansivity of the material. Substituting the given values, we have: V = 1.0018 cm³ = V₀(1 + 2.0 x 10^-5 x 30) Simplifying the expression, we get: V₀ = V / (1 + γΔT) = 1.0018 cm³ / (1 + 2.0 x 10^-5 x 30) Calculating this expression gives us: V₀ = 1.0000 cm³ Therefore, the original volume of the metal ball is 1.0000 cm³. Hence, the answer is 1.0000 cm³.

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Thermal Expansion

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When a metal ball is heated through 30oC,its volume becomes 1.0018cm3. If the linear expansivity of the material of the ball is 2.0 x 10-5 K-1, calculate it...

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