A charge of 1.6 x 10-10C is placed in a uniform electric field of intensity 2.0 x 105 NC-1. calculate the magnitude of the electric force exerted on the cha...
Question 1 Report
A charge of 1.6 x 10-10C is placed in a uniform electric field of intensity 2.0 x 105 NC-1. calculate the magnitude of the electric force exerted on the change
Answer Details
The magnitude of electric force can be calculated using the formula:
Electric force (F) = charge (Q) x electric field intensity (E)
Substituting the given values, we get:
F = Q x E
F = (1.6 x 10^-10 C) x (2.0 x 10^5 NC^-1)
F = 3.2 x 10^-5 N
Therefore, the magnitude of the electric force exerted on the charge is 3.2 x 10^-5 N. The correct option is (C) 3.2 x 10^-5 N.
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