The charge of magnitude 1.6 x 10 −19 − 19 C is placed in a uniform electric field of intensity 1200Vm−1 − 1 . Calculate its acceleration, if the mass of the...

Answer Details

To calculate the acceleration of a charge in an electric field, we start by determining the force acting on the charge. The force \( F \) experienced by a charge \( q \) in a uniform electric field \( E \) is given by the equation:

F = q * E

We are given:

• Charge, q = 1.6 x 10^-19 C
• Electric field, E = 1200 V/m

Substituting these values into the equation for force:

F = 1.6 x 10^-19 C * 1200 V/m

This results in:

F = 1.92 x 10^-16 N

Next, we use Newton’s second law of motion to find the acceleration \( a \) of the charge. This law is given as:

F = m * a

Rearranging for \( a \), we have:

a = F / m

We know:

• Force, F = 1.92 x 10^-16 N
• Mass, m = 9.1 x 10^-31 kg

Substituting these values in the equation for acceleration:

a = \(\frac{1.92 x 10^{-16} N}{9.1 x 10^{-31} kg}\)

Calculating the above expression gives:

a ≈ 2.11 x 10¹⁴ ms^-2

Therefore, the acceleration of the charge is approximately 2.11 x 10¹⁴ ms^-2.