Calculate the quantity of heat for copper rod whose thermal capacity is 400Jk−1 − 1 for a temperature change of 60ºC to 80ºC

Assessment: JAMB UTME - Physics - 2024 Subject: Physics

Question 1 Report

Calculate the quantity of heat for copper rod whose thermal capacity is 400Jk−1 − 1  for a temperature change of 60ºC to  80ºC
Answer Details

To calculate the quantity of heat absorbed or released by a substance, we can use the formula:


Q = C × ΔT


where:


  • Q is the quantity of heat.
  • C is the thermal capacity of the substance.
  • ΔT is the change in temperature.

Given:


  • C = 400 J/°C
  • Initial temperature = 60°C
  • Final temperature = 80°C

First, calculate the change in temperature:


ΔT = Final temperature - Initial temperature = 80°C - 60°C = 20°C


Now, substitute the values into the formula to find the quantity of heat:


Q = 400 J/°C × 20°C


Calculate the answer:


Q = 8000 J


Since the options provided are in kilojoules (KJ), we need to convert joules (J) to kilojoules (1 KJ = 1000 J):


Q = 8000 J ÷ 1000 = 8 KJ


Therefore, the quantity of heat for the copper rod, given the specified conditions, is 8 KJ.

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