An object of volume 1 m 3 and mass 2kg is totally immersed in a liquid of density 1 kgm-3 . Calculate its apparent weight.

Answer Details

The apparent weight of the object is the difference between the actual weight of the object and the buoyant force acting on it when it is immersed in a fluid. The buoyant force is equal to the weight of the fluid displaced by the object.
In this case, the volume of the object is 1 m^3 and its mass is 2 kg, which means its density is 2 kg/m^3. The density of the liquid is given as 1 kg/m^3. Since the density of the object is greater than the density of the liquid, it will sink in the liquid.
When the object is totally immersed in the liquid, it will displace a volume of liquid equal to its own volume. Therefore, the weight of the displaced liquid is given by the product of the volume and density of the liquid, which is 1 m^3 * 1 kg/m^3 = 1 kg. This is also the buoyant force acting on the object.
The actual weight of the object is 2 kg * 9.81 m/s^2 = 19.62 N (where 9.81 m/s^2 is the acceleration due to gravity).
Therefore, the apparent weight of the object is the difference between the actual weight and the buoyant force, which is 19.62 N - 1 kg * 9.81 m/s^2 = 9.81 N.
Therefore, the apparent weight of the object is 9.81 N, which is closest to.