Find all real numbers x which satisfy the inequality 13 1 3 (x + 1) - 1 > 15 1 5 (x + 4)

Question 1 Report

Find all real numbers x which satisfy the inequality $\frac{1}{3}$ (x + 1) - 1 > $\frac{1}{5}$ (x + 4)

x < 11

x < -1

x > 6

x > 11

Answer Details

$\frac{1}{3}$ (x + 1) - 1 > $\frac{1}{5}$ (x + 4)
= $\frac{x + 1}{3}$ - 1 > $\frac{x + 4}{5}$
$\frac{x + 1}{3}$ - $\frac{x + 4}{5}$ - 1 > 0
= $\frac{5 x + 5 - 3 x - 12}{15}$
= 2x - 7 > 15
= 2x > 12
= x > 11

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Inequalities

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