A piece of metal of mass 50g is cooled from 80oC to 20oC. Calculate the amount of heat lost. (specific heat capacity of the material of metal = 450Jkg-1K-1)

Assessment: WAEC SSCE - Physics - 2000 (Objective) Subject: Physics

Question 1 Report

A piece of metal of mass 50g is cooled from 80^oC to 20^oC. Calculate the amount of heat lost. (specific heat capacity of the material of metal = 450Jkg^-1K^-1)

4.50 x 10³J

2.25 x 10³J

1.80 x 10³J

1.35 x 10³J

Answer Details

The amount of heat lost by an object is given by the formula: Q = mcΔT where Q is the amount of heat lost or gained, m is the mass of the object, c is the specific heat capacity of the material, and ΔT is the change in temperature. In this question, the mass of the metal is given as 50g, which is 0.05kg. The specific heat capacity of the material of the metal is given as 450Jkg^-1K^-1. The change in temperature is 80^oC - 20^oC = 60^oC. Substituting the given values into the formula: Q = (0.05kg)(450Jkg^-1K^-1)(60K) Q = 1.35 x 10³J Therefore, the amount of heat lost by the piece of metal is 1.35 x 10³J. Option (d) is the correct answer.

Read lesson note on Heat Energy (WAEC)

Heat Energy

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A piece of metal of mass 50g is cooled from 80oC to 20oC. Calculate the amount of heat lost. (specific heat capacity of the material of metal = 450Jkg-1K-1)

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